Termination Proof Script
Consider the TRS R consisting of the rewrite rules
|  | 
| 1: |  | f(f(x,y,z),u,f(x,y,v)) | → f(x,y,f(z,u,v)) | 
| 2: |  | f(x,y,y) | → y | 
| 3: |  | f(x,y,g(y)) | → x | 
| 4: |  | f(x,x,y) | → x | 
| 5: |  | f(g(x),x,y) | → y | 
|  | 
There are 2 dependency pairs:
|  | 
| 6: |  | F(f(x,y,z),u,f(x,y,v)) | → F(x,y,f(z,u,v)) | 
| 7: |  | F(f(x,y,z),u,f(x,y,v)) | → F(z,u,v) | 
|  | 
Consider the SCC {6,7}.
By taking the AF π with
π(F) = π(g) = 1
and π(f) = [1, 3] together with
the lexicographic path order with
empty precedence,
the rules in {1-7}
are strictly decreasing.
Hence the TRS is terminating.
Tyrolean Termination Tool  (0.01 seconds)
  ---  May 4, 2006